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Among halogens, the correct order of amount of energy released in electron gain (electron gain enthalpy) is
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(c) $\mathrm{F} < \mathrm{Cl}>\mathrm{Br}>\mathrm{I}$
(c) $\mathrm{F} < \mathrm{Cl}>\mathrm{Br}>\mathrm{I}$
As we move in a group from $\mathrm{Cl}$ to $\mathrm{I}$, the electron gain enthalpy (i.e., energy released in electron gain) become less and less negative due to corresponding increase in the atomic size.
However, the electron gain enthalpy of $F$ is less negative than that of $\mathrm{Cl}$ due to its small size. Thus, the negative electron gain enthalpy among halogens follows the order:
$\mathrm{F} < \mathrm{Cl}>\mathrm{Br}>\mathrm{I}$
However, the electron gain enthalpy of $F$ is less negative than that of $\mathrm{Cl}$ due to its small size. Thus, the negative electron gain enthalpy among halogens follows the order:
$\mathrm{F} < \mathrm{Cl}>\mathrm{Br}>\mathrm{I}$
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