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Among $\mathrm{Me}_{3}\mathrm{N}, \mathrm{C}_{5} \mathrm{H}_{5} \mathrm{N}$ and MeCN
(Me $=$ methyl group) the electronegativity of $\mathrm{N}$ is in the order
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(Me $=$ methyl group) the electronegativity of $\mathrm{N}$ is in the order
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The correct answer is:
$\mathrm{MeCN}>\mathrm{C}_{\mathrm{g}} \mathrm{H}_{\mathrm{s}} \mathrm{N}>\mathrm{Me}_{3} \mathrm{N}$
$\because$ In Me $_{3} \mathrm{N} \rightarrow \mathrm{N}$ is $s p^{3}$ -hybrid
and in $\mathrm{MeCN} \rightarrow \mathrm{N}$ is $s p$ -hybrid Also electronegativity of any element $\alpha \%$ $s$ -character in hybrid orbitals. Thus, order of electronegativity for nitrogen is
$$
\mathrm{MeCN}>\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{N} < \mathrm{Me}_{3} \mathrm{N}
$$
and in $\mathrm{MeCN} \rightarrow \mathrm{N}$ is $s p$ -hybrid Also electronegativity of any element $\alpha \%$ $s$ -character in hybrid orbitals. Thus, order of electronegativity for nitrogen is
$$
\mathrm{MeCN}>\mathrm{C}_{5} \mathrm{H}_{5} \mathrm{N} < \mathrm{Me}_{3} \mathrm{N}
$$
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