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Among the compounds
(i) $\mathrm{H}-\mathrm{C} \equiv \mathrm{C}-\mathrm{COOH}$
(ii) $\mathrm{CH}_2=\mathrm{CH}-\mathrm{COOH}$
(iii) $\mathrm{CH}_3-\mathrm{CH}_2 \mathrm{COOH}$ and
(iv) $\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{OH}$
The correct order of acid strength is
Options:
(i) $\mathrm{H}-\mathrm{C} \equiv \mathrm{C}-\mathrm{COOH}$
(ii) $\mathrm{CH}_2=\mathrm{CH}-\mathrm{COOH}$
(iii) $\mathrm{CH}_3-\mathrm{CH}_2 \mathrm{COOH}$ and
(iv) $\mathrm{CH}_3-\mathrm{CH}_2-\mathrm{OH}$
The correct order of acid strength is
Solution:
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Verified Answer
The correct answer is:
(i) > (ii) > (iii) > (iv)
Carboxylic acids are more acidic than alcohol. As the 's'-character in the $\mathrm{C}_{\mathrm{x}}$ increases, the acidity of carboxylic acid increases.
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