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Among the following carbocations :
(I) \(\mathrm{Ph}_{2}\stackrel{+}{\mathrm{C}} \mathrm{CH}_{2} \mathrm{Me}(\mathrm{II}) \mathrm{Ph} \mathrm{CH}_{2} \mathrm{CH}_{2} \stackrel{+}{\mathrm{C}} \mathrm{HPh}\)
(III) \(\mathrm{Ph}_{2} \mathrm{CH} \stackrel{+}{\mathrm{C}} \mathrm{HMe}\) (IV) \(\mathrm{Ph}_{2} \mathrm{C}(\mathrm{Me}) \stackrel{+}{\mathrm{C}} H_{2}\) the order of stability is :
Options:
(I) \(\mathrm{Ph}_{2}\stackrel{+}{\mathrm{C}} \mathrm{CH}_{2} \mathrm{Me}(\mathrm{II}) \mathrm{Ph} \mathrm{CH}_{2} \mathrm{CH}_{2} \stackrel{+}{\mathrm{C}} \mathrm{HPh}\)
(III) \(\mathrm{Ph}_{2} \mathrm{CH} \stackrel{+}{\mathrm{C}} \mathrm{HMe}\) (IV) \(\mathrm{Ph}_{2} \mathrm{C}(\mathrm{Me}) \stackrel{+}{\mathrm{C}} H_{2}\) the order of stability is :
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Verified Answer
The correct answer is:
$I>\mathrm{II}>\mathrm{III}>\mathrm{IV}$
The order of stability of carbocation is $3^{\circ}$ benzylic $>2^{\circ}$ benzylic $>2^{*}>1^{*}$ Thus, the correct order of stability will be
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