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Question: Answered & Verified by Expert
Among the following metal carbonyls, the $\mathrm{C}-\mathrm{O}$ bond order is lowest in
ChemistryCoordination CompoundsJEE AdvancedJEE Advanced 2007 (Paper 2)
Options:
  • A
    $\left[\mathrm{MO}(\mathrm{CO})_6\right]^{+}$
  • B
    $\left[\mathrm{Fe}(\mathrm{CO})_5\right]$
  • C
    $\left[\mathrm{Cr}(\mathrm{CO})_6\right]$
  • D
    $\left[\mathrm{V}(\mathrm{CO})_6\right]^{-}$
Solution:
1553 Upvotes Verified Answer
The correct answer is:
$\left[\mathrm{Fe}(\mathrm{CO})_5\right]$
(a) $\mathrm{Mn}^{+}=3 d^5 4 s^1$ In presence of $\mathrm{CO}$ effective configuration $=3 d^6 4 s^0, 3$ lone pair for back bonding with vacant orbital of $\mathrm{C}$ in $\mathrm{CO}$.
(b) $\mathrm{Fe}^{\circ}=3 d^6 4 s^2$ in presence of $\mathrm{CO}$ effective configuration $=3 d^8, 4$ lone pair for back bonding with $\mathrm{CO}$.
(c) $\mathrm{Cr}^{\circ}=3 d^5 4 s^1$, effective configuration $=3 d^6$
3 lone pair for back bonding with $\mathrm{CO}$.
(d) $\mathrm{V}^{-}=3 d^4 s^2$, effective configuration $=3 d^6, 3$ lone pair for back bonding with $\mathrm{CO}$. Maximum back bonding in $\mathrm{Fe}(\mathrm{CO})_5$, therefore $\mathrm{CO}$ bond order is lowest here.

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