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Among the following set of quantum numbers, the impossible set is
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The correct answer is:
\begin{array}{rrrr}
n & 1 & m & s \\
3 & 2 & -3 & -\frac{1}{2}
\end{array}
n & 1 & m & s \\
3 & 2 & -3 & -\frac{1}{2}
\end{array}
For each value of $n, l=n-1$ (max.) and for each value of $1, m=-1$ to +1 .
Thus, for $1=2, m=-2,-1,0,1,2$ and $m \neq-3$.
Thus, for $1=2, m=-2,-1,0,1,2$ and $m \neq-3$.
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