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Question: Answered & Verified by Expert
Among the following set of quantum numbers, the impossible set is
ChemistryStructure of AtomJIPMERJIPMER 2017
Options:
  • A \begin{array}{rrrr}
    n & 1 & m & s \\
    3 & 2 & -3 & -\frac{1}{2}
    \end{array}
  • B \begin{array}{cccc}
    n & 1 & m & s \\
    4 & 0 & 0 & \frac{1}{2}
    \end{array}
  • C \begin{array}{cccc}
    n & 1 & m & s \\
    5 & 3 & 0 & -\frac {1}{2}
    \end{array}
  • D \begin{array}{rrrr}
    n & 1 & m & s \\
    3 & 2 & -3 & \frac{1}{2}
    \end{array}
Solution:
1292 Upvotes Verified Answer
The correct answer is: \begin{array}{rrrr}
n & 1 & m & s \\
3 & 2 & -3 & -\frac{1}{2}
\end{array}
For each value of $n, l=n-1$ (max.) and for each value of $1, m=-1$ to +1 .
Thus, for $1=2, m=-2,-1,0,1,2$ and $m \neq-3$.

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