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Among the following, the number of compounds than can react with $\mathrm{PCl}_5$ to give $\mathrm{POCl}_3$ is $\mathrm{O}_2, \mathrm{CO}_2, \mathrm{SO}_2, \mathrm{H}_2 \mathrm{O}, \mathrm{H}_2 \mathrm{SO}_4, \mathrm{P}_4 \mathrm{O}_{10}$.
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The correct answer is:
4
$$
\text { } \mathrm{PCl}_5 \text { produces } \mathrm{POCl}_3 \text { with the following reagents }
$$
\text { } \mathrm{PCl}_5 \text { produces } \mathrm{POCl}_3 \text { with the following reagents }
$$
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