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Among the following, the species that is both tetrahedral and diamagnetic is -
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Verified Answer
The correct answer is:
$\mathrm{Ni}(\mathrm{CO})_{4}$
$\begin{array}{l}
{\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]} \\
\mathrm{Ni}^{\circ}=3 \mathrm{~d}^{8} 4 \mathrm{~s}^{2} \\
\mathrm{CO}=\mathrm{SFL}, \mathrm{Ni}^{\circ}=3 \mathrm{~d}^{10} 4 \mathrm{~s}^{0}
\end{array}$
{\left[\mathrm{Ni}(\mathrm{CO})_{4}\right]} \\
\mathrm{Ni}^{\circ}=3 \mathrm{~d}^{8} 4 \mathrm{~s}^{2} \\
\mathrm{CO}=\mathrm{SFL}, \mathrm{Ni}^{\circ}=3 \mathrm{~d}^{10} 4 \mathrm{~s}^{0}
\end{array}$
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