$\begin{aligned} \mathrm{B} & =\frac{\mu_0}{4 \pi} \frac{\mathrm{Idl} \sin \theta}{\mathrm{r}^2} \\ \mu_0 & =\frac{\mathrm{Br}^2}{\mathrm{Idl}}=\frac{\text { Tesla } \mathrm{m}^2}{\mathrm{Amp} \mathrm{m}} \\ & =\frac{\text { Weber }}{\text { Ampere meter }}\end{aligned}$