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Question: Answered & Verified by Expert
Among the following, which is not the $\pi$-bonded organometallic compound
ChemistryCoordination CompoundsJEE Main
Options:
  • A $\left(\mathrm{CH}_3\right)_4 \mathrm{Sn}$
  • B $\mathrm{K}\left[\mathrm{PtCl}_3\left(\eta^2-\mathrm{C}_2 \mathrm{H}_4\right)\right]$
  • C $\mathrm{Fe}\left(\eta^5-\mathrm{C}_5 \mathrm{H}_5\right)_2$
  • D $\mathrm{Cr}\left(\eta^6-\mathrm{C}_6 \mathrm{H}_6\right)_2$
Solution:
2517 Upvotes Verified Answer
The correct answer is: $\left(\mathrm{CH}_3\right)_4 \mathrm{Sn}$
$\left(\mathrm{CH}_3\right)_4 \mathrm{Sn}$ is an organometallic compound where tin is bonded to four methyl groups via single σ-bonds. It does not involve $\pi$-bonding. The other compounds listed involve π-interactions with ligands like ethylene ($\eta^2$), cyclopentadienyl ($\eta^5$), and benzene (\eta^6).

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