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Question: Answered & Verified by Expert
An 80 μC charge is given to the 4 μF capacitor in the circuit shown in the figure so that the upper plate A is positively charged. An unknown resistance R is connected in the left limb. As soon as the switch S in the central limb is closed, a current of 2 A flows through the 2 Ω resistor in the central limb. The capacitive time constant for the circuit is

PhysicsCurrent ElectricityJEE Main
Options:
  • A 56  μ s
  • B μ s
  • C 200  μ s
  • D 40  μ s
Solution:
2810 Upvotes Verified Answer
The correct answer is: 40  μ s
Potential difference across the central limb = 16 V = Potential difference across 16 Ω = Potential difference across the left limb.

current through 16 Ω = 1 A

current through the left limb = 1 A  and

R=11 Ω

τc=162+2ohms×4×10-6 F=40 μs

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