An AB solid has CsCl type of structure, where A occupies corner. If the atoms from corners along one of the body diagonal are removed, the formula of a the solid would be

Question

An AB solid has CsCl type of structure, where A occupies corner. If the atoms from corners along one of the body diagonal are removed, the formula of a the solid would be, A 7 B 8, A 5 B 6, A 3 B 4, A 4 B 3

MARKS App · Accepted Answer

Along a body diagonal two corners will be removed i.e. 2 atoms decrease So A atoms = 6 × 1 8 = 3 4 B atoms = 1 (m body centre) So A : B = 3 4 : 1 = 3 : 4 Hence formula A 3 B 4 .

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