An AC voltage is applied to a resistor of resistance $ R $ and an inductor of inductance $ L $ in series. If $ R $ and the inductive reactance are both equal to $ 3 \Omega $, the phase difference between the applied voltage and the current in the circuit is

Question

An AC voltage is applied to a resistor of resistance $ R $ and an inductor of inductance $ L $ in series. If $ R $ and the inductive reactance are both equal to $ 3 \Omega $, the phase difference between the applied voltage and the current in the circuit is, $ \pi / 6 $, $ \pi / 4 $, $ \pi / 2 $, Zero

MARKS App · Accepted Answer

Here, Resistance, R = 3 Ω Inductive reactance, X L = 3 Ω The phase difference between the applied voltage and the current in the circuit is tan ϕ = X L R = 3 Ω 3 Ω = 1 ϕ = tan - 1 1 or ϕ = π 4

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