An acid dissociated to 1.5% in its 0.1 M solution. Calculate its dissociation constant.

Open MARKS Web Download App

Search any question & find its solution

Question: Answered & Verified by Expert

An acid dissociated to $1.5 \%$ in its $0.1 \mathrm{M}$ solution. Calculate its dissociation constant.

ChemistryChemical EquilibriumMHT CETMHT CET 2022 (06 Aug Shift 2)

Options:

A $1.2 \times 10^{-5}$
B $2.25 \times 10^{-5}$
C $1.1 \times 10^{-5}$
D $1.5 \times 10^{-5}$

Solution:

2828 Upvotes Verified Answer

The correct answer is: $2.25 \times 10^{-5}$

$\begin{aligned} & K_a=\alpha^2 C \\ & =\left(\frac{1.5}{100}\right)^2 \times 0.1 \\ & =2.25 \times 10^{-5}\end{aligned}$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.

Use on iOS or Desktop Download from Google Play