An active nucleus decays to one-third 1 3 in 20 Hrs . The fraction of original activity remaining after 80 Hrs is

Question

An active nucleus decays to one-third 1 3 in 20 Hrs . The fraction of original activity remaining after 80 Hrs is, 1 16, 1 81, 1 36, 1 54

MARKS App · Accepted Answer

We know, N N 0 = 2 3 t / T From the given data, N 0 3 N 0 = 1 2 20 T 1 3 = 1 2 20 T . . . 1 N N 0 = 1 2 80 T . . . 2 From 1 and 2 , ∴ N N 0 = 1 3 3 = 1 81

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