Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
An air-filled parallel plate capacitor has capacitance C. The capacitor is connected through a resistor to a voltage source providing a constant potential difference V



A dielectric plate with a dielectric constant K is inserted into the capacitor, filling it completely. After the equilibrium is established plate is quickly removed. Find the amount of heat generated in the resistor by the time, the equilibrium is re-established.
PhysicsCapacitanceJEE Main
Options:
  • A CV2 K- 1
  • B 12CV2 K- 1
  • C CV2 K- 12
  • D 12CV2K2- 1
Solution:
2623 Upvotes Verified Answer
The correct answer is: 12CV2 K- 1

After the insertion of the slab and steady-state is reached, the energy stored in the capacitor is

Ui=12KCV2

After the removal of the lab and steady-state is reached, the energy stored in the capacitor is

Uf=12CV2

Heat=12CK- 1V2

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.