Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
An alkali metal hydride \( (\mathrm{NaH}) \) reacts with diborane in ' \( A \) ' to give a tetrahedral compound 'ET
which is extensively used as reducing agent in organic synthesis. The compounds 'A' and 'ET
respectively are
Chemistryp Block Elements (Group 13 & 14)KCETKCET 2015
Options:
  • A \( C_{2} H_{6} \) and \( C_{2} H_{5} \mathrm{Na} \)
  • B \( \mathrm{CH}_{3} \mathrm{COCH}_{3} \) and \( \mathrm{B}_{3} \mathrm{~N}_{3} \mathrm{H}_{6} \)
  • C \( C_{6} H_{6} \) and \( \mathrm{NaBH}_{4} \)
  • D \( \left(C_{2} H_{5}\right)_{2} O \) and \( \mathrm{NaBH}_{4} \)
Solution:
2909 Upvotes Verified Answer
The correct answer is: \( \left(C_{2} H_{5}\right)_{2} O \) and \( \mathrm{NaBH}_{4} \)
The reaction involved is
$2 N a H+B_{2} H_{6}^{(A)\left(C_{2} H_{5}\right)_{2} O}$ (B) $2 N a B H_{4}$
The compound (B) is sodium borohydride ( \( \mathrm{NaBH}_{4} \) ) which is a reducing agent in many organic syntheses.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.