Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
An alkene (A) on ozonolysis gives a mixture of two carbonyl compounds. Mixture on Clemmensen reduction gives just one alkane (B) . (B) is the lowest alkane which in pure form can not be prepared by standard Wurtz method. (A) is
ChemistryHydrocarbonsNEET
Options:
  • A MeCH=CHMe
  • B MeCH2CH=CMe2
  • C MeCH2CH2CH2CH=CEt2
  • D MeCH2CH2CH=C(Me)Et
Solution:
1415 Upvotes Verified Answer
The correct answer is: MeCH2CH=CMe2
Simplest alkane which cannot be prepared by wurtz reaction is propane. So the alkene must be unsymmetrical having six carbon, which can give two different carbonyl each contain three carbons.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.