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An alkyl halide reacts with alcoholic ammonia in a sealed tube, the product formed will be
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a mixture of all the three
When an alkyl halide reacts with alcoholic ammonia in a sealed tube then a mixture of primary, secondary and tertiary amine is formed
$R \mathrm{X}+\mathrm{NH}_{3} \longrightarrow R \mathrm{NH}_{2}+\mathrm{H} X$
pri-amine
$\mathrm{RNH}_{2}+X R \longrightarrow R_{2} \mathrm{NH}+\mathrm{H} X$
$R_{2} \mathrm{NH}+X R \longrightarrow R_{3} \mathrm{~N}+\mathrm{H} X$
$R \mathrm{X}+\mathrm{NH}_{3} \longrightarrow R \mathrm{NH}_{2}+\mathrm{H} X$
pri-amine
$\mathrm{RNH}_{2}+X R \longrightarrow R_{2} \mathrm{NH}+\mathrm{H} X$
$R_{2} \mathrm{NH}+X R \longrightarrow R_{3} \mathrm{~N}+\mathrm{H} X$
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