An alpha nucleus of energy 1 2 m v 2 bombards on a heavy nuclear target of the charge Ze . Then the distance of closest approach for the alpha nucleus will be proportional to

Question

An alpha nucleus of energy 1 2 m v 2 bombards on a heavy nuclear target of the charge Ze . Then the distance of closest approach for the alpha nucleus will be proportional to, Z 2 v 2, v 2 Z 2, Z v 2, v 2 Z

MARKS App · Accepted Answer

For the closest approach, kinetic energy is converted into potential energy 1 2 mv 2 = 1 4 π ε 0 q 1 q 2 r 0 = 1 4 π ε 0 Ze 2 e r 0 r 0 ∝ Z v 2

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