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An altermating current is flowing through a series $L-C - R$ circuit. It is found that the current reaches a value of $1 \mathrm{mA}$ at both $200 \mathrm{Hz}$ and $800 \mathrm{Hz}$ frequency. What is the resonance frequency of the circuit?
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Verified Answer
The correct answer is:
$400 \mathrm{Hz}$
$\because$ Resonance frequency, $f_{0}=\sqrt{f_{1} f_{2}}$
$$
=\sqrt{200 \times 800}=400 \mathrm{Hz}
$$
$$
=\sqrt{200 \times 800}=400 \mathrm{Hz}
$$
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