Search any question & find its solution
Question:
Answered & Verified by Expert
An alternating current in a circuit is given by $I=20 \sin (100 \pi t+0.05 \pi)$ A. The r.m.s. value and the frequency of current respectively are
Options:
Solution:
1191 Upvotes
Verified Answer
The correct answer is:
$10 \sqrt{2} \mathrm{A}$ and $50 \mathrm{Hz}$
Given, $I=20 \sin (100 \pi t+0.05 \pi)$
The root mean square value of alternating
$$
\text { current }=l_{\mathrm{ms}}=\frac{l_{0}}{\sqrt{2}}=\frac{20}{\sqrt{2}}=10 \sqrt{2} \mathrm{A}
$$
Also, $\quad \omega=100 \pi$
$\Rightarrow \quad 2 \pi f=100 \pi$ or $f=50 \mathrm{Hz}$
The root mean square value of alternating
$$
\text { current }=l_{\mathrm{ms}}=\frac{l_{0}}{\sqrt{2}}=\frac{20}{\sqrt{2}}=10 \sqrt{2} \mathrm{A}
$$
Also, $\quad \omega=100 \pi$
$\Rightarrow \quad 2 \pi f=100 \pi$ or $f=50 \mathrm{Hz}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.