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An alternating current is given by the equation $i=i_1 \cos \omega t+i_2 \sin \omega t$. The r.m.s. current is given by
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The correct answer is:
$\frac{1}{\sqrt{2}}\left(i_1^2+i_2^2\right)^{1 / 2}$
$i_{r m s}=\sqrt{\frac{i_1^2+i_2^2}{2}}=\frac{1}{\sqrt{2}}\left(i_1^2+i_2^2\right)^{1 / 2}$
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