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An amine $\mathrm{C}_{3} \mathrm{H}_{9} \mathrm{N}$ reacts with benzene sulphonyl chloride to form a white precipitate which is insoluble in $\mathrm{aq} . \mathrm{NaOH}$. The amine is
Options:
- A
- B
- C
- D
Solution:
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Verified Answer
The correct answer is:
Since, the amine gives white precipitate with benzene sulphonyl chloride which is insoluble in aq. $\mathrm{Na} \mathrm{OH},$ so Ti must be a secondary amine lie. amine having RNHR group).
Among the given compound, only
is a secondary amine, so it represents the structure of given amine.
Among the given compound, only
is a secondary amine, so it represents the structure of given amine.
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