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An ammeter and a voltmeter of resistance $R$ are connected in series to an electric cell of negligible internal resistance. Their reading are $A$ and $V$ respectively. If another resistance $R$ is connected in parallel with the voltmeter, then
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$A$ will increase and $V$ will decrease
The effective resistance will decrease when resistance $R$ is connected in parallel with the voltmeter.
According to Ohm's law, $\mathrm{V}=\mathrm{IR}$ or, $\mathrm{R}=\frac{\mathrm{V}}{\mathrm{I}}$ Here, as $R$ decreases, so $V$ decrease and $I$ should increase.
According to Ohm's law, $\mathrm{V}=\mathrm{IR}$ or, $\mathrm{R}=\frac{\mathrm{V}}{\mathrm{I}}$ Here, as $R$ decreases, so $V$ decrease and $I$ should increase.
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