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An arc of a circle of radius $R$ subtends an angle ${ }^{\frac{\pi}{2}}$ at the centre. It carries a current $i$. The magnetic field at the centre will be
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The correct answer is:
$\frac{\mu_0 i}{8 R}$
$B=\frac{\mu_0}{4 \pi} \frac{\theta i}{r}=\frac{\mu_0}{4 \pi} \times \frac{\pi}{2} \times \frac{i}{R}=\frac{\mu_0 i}{8 R}$
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