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An athlete completes one round of a circular track of radius $R$ in $40 \mathrm{sec}$. What will be his displacement at the end of $2 \mathrm{~min} .20 \mathrm{sec}$
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The correct answer is:
2R
Total time of motion is $2 \mathrm{~min} 20 \mathrm{sec}=140 \mathrm{sec}$.
As time period of circular motion is $40 \mathrm{sec}$ so in $140 \mathrm{sec}$. athlete will complete 3.5 revolution i.e., He will be at diametrically opposite point i.e., Displacement $=2 R$.
As time period of circular motion is $40 \mathrm{sec}$ so in $140 \mathrm{sec}$. athlete will complete 3.5 revolution i.e., He will be at diametrically opposite point i.e., Displacement $=2 R$.
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