An electric appliance supplies 6000 J min - 1 , heat to the system. If the system delivers a power of 90 W . How long it would take to increase the internal energy by 2 . 5 × 10 3 J ?

Question

An electric appliance supplies 6000 J min - 1 , heat to the system. If the system delivers a power of 90 W . How long it would take to increase the internal energy by 2 . 5 × 10 3 J ?, 2 . 5 × 10 1 s, 2 . 5 × 10 2 s, 2 . 4 × 10 3 s, 4 . 1 × 10 1 s

MARKS App · Accepted Answer

Recall the formula of the first law of thermodynamics in terms of change in internal energy and work done by the system, Δ U = Q - W , given, Δ U = 2500 J , Q = 6000 60 × t = 100 t J and W = P × t = 90 t , ⇒ 2500 J = 100 t J - 90 t J ⇒ t = 2 . 5 × 10 2 s .

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