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Question: Answered & Verified by Expert
An electric bulb of $100 \mathrm{~W}$ is connected to a supply of electricity of $220 \mathrm{~V}$. Resistance of the filament is
PhysicsCurrent ElectricityVITEEEVITEEE 2011
Options:
  • A $484 \Omega$
  • B $100 \Omega$
  • C $22000 \Omega$
  • D $242 \Omega$
Solution:
2882 Upvotes Verified Answer
The correct answer is: $484 \Omega$
Power $\mathrm{P}=\frac{V^{2}}{R}=\frac{220 \times 220}{100}=484 \mathrm{~W}$

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