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An electric bulb of $100 \mathrm{~W}$ is connected to a supply of electricity of $220 \mathrm{~V}$. Resistance of the filament is
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$484 \Omega$
Power $\mathrm{P}=\frac{V^{2}}{R}=\frac{220 \times 220}{100}=484 \mathrm{~W}$
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