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An electric current $^{\prime} I^{\prime}$ enters and leaves a uniform circular wire of radius $r$ through diametrically opposite points. A particle carrying a charge $q$ moves along the axis of the circular wire with speed $v$. What is the magnetic force experienced by the particle when it passes through the centre of the circle?
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The correct answer is:
Zero
Given, electric current in circular wire $=I$
Radius of wire $=r$
Charge on particle $=q$
Speed of the particle $=v$
The given loop can be as shown in the figure below. $1 / 2$
$\because$ Net magnetic field at the centre $=0$
So, magnetic force $\mathbf{F}_{\text {magnetic }}=q(\mathbf{v} \times \mathbf{B})=0$ So, the magnetic force experienced by the particle when it passes through the centre is $F=0$
Radius of wire $=r$
Charge on particle $=q$
Speed of the particle $=v$
The given loop can be as shown in the figure below. $1 / 2$
$\because$ Net magnetic field at the centre $=0$
So, magnetic force $\mathbf{F}_{\text {magnetic }}=q(\mathbf{v} \times \mathbf{B})=0$ So, the magnetic force experienced by the particle when it passes through the centre is $F=0$
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