Search any question & find its solution
Question:
Answered & Verified by Expert
An electric field of $1000 \mathrm{~V} / \mathrm{m}$ is applied to an electric dipole at angle of $45^{\circ}$. The value of electric dipole moment is $10^{-29} \mathrm{C} \cdot \mathrm{m} .$ What is the potential energy of the electric dipole?
Options:
Solution:
1080 Upvotes
Verified Answer
The correct answer is:
$-7 \times 10^{-27} \mathrm{~J}$
Potential energy of a dipole is given by $\mathrm{U}=-\overrightarrow{\mathrm{P}} \overrightarrow{\mathrm{E}}$
$=-P E \cos \theta$
[Where $\theta=$ angle between dipole and perpendicular to the field $=-\left(10^{-29}\right)\left(10^{3}\right) \cos 45^{\circ}$
$=-0.707 \times 10^{-26} \mathrm{~J}=-7 \times 10^{-27} \mathrm{~J}$
$=-P E \cos \theta$
[Where $\theta=$ angle between dipole and perpendicular to the field $=-\left(10^{-29}\right)\left(10^{3}\right) \cos 45^{\circ}$
$=-0.707 \times 10^{-26} \mathrm{~J}=-7 \times 10^{-27} \mathrm{~J}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.