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An electric kettle takes $4 \mathrm{~A}$ current at $220 \mathrm{~V}$. How much time will it take to boil $1 \mathrm{~kg}$ of water from temperature $20^{\circ} \mathrm{C}$ ? The temperature of boiling water is $100^{\circ} \mathrm{C}$.
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Verified Answer
The correct answer is:
$6.3 \mathrm{~min}$
$$
\begin{aligned}
& \text { Vit }=m c \Delta \theta \\
& t=\frac{1 \times 4200 \times 80}{220 \times 4}=381.8 \mathrm{~s}=6.36 \mathrm{~min}
\end{aligned}
$$
\begin{aligned}
& \text { Vit }=m c \Delta \theta \\
& t=\frac{1 \times 4200 \times 80}{220 \times 4}=381.8 \mathrm{~s}=6.36 \mathrm{~min}
\end{aligned}
$$
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