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An electric wire is connected across a cell of e.m.f. E. The current $I$ is measured by an ammeter of resistance $R$. According to ohm's law
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The correct answer is:
$E=I R$
Correct option is B. \(E=I R\)
From ohm's law potential drop \(=\) current \(\mathrm{x}\) resistance mathmatically \(E=I R\)
From ohm's law potential drop \(=\) current \(\mathrm{x}\) resistance mathmatically \(E=I R\)
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