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Question:
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An electromagnetic wave going through vacuum is described by
$$
E=E_{0} \sin (k x-\omega t)
$$
Which of the following is/are independent of the wavelength?
Options:
$$
E=E_{0} \sin (k x-\omega t)
$$
Which of the following is/are independent of the wavelength?
Solution:
2583 Upvotes
Verified Answer
The correct answer is:
$\mathrm{k} / \omega$
$\frac{k}{\omega}$ is independent of $\lambda$
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