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An electromagnetic wave passes through space and its equation is given by $\mathrm{E}=\mathrm{E}_{0} \sin (\omega \mathrm{t}-\mathrm{kx})$
where $\mathrm{E}$ is electric field. Energy density of electromagnetic wave in space is
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where $\mathrm{E}$ is electric field. Energy density of electromagnetic wave in space is
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Verified Answer
The correct answer is:
$\frac{1}{2} \varepsilon_{0} \mathrm{E}_{0}^{2}$
Energy density
$$
=\varepsilon_{0} \mathrm{E}_{\mathrm{rm}}^{2}=\varepsilon_{0}\left(\frac{\mathrm{E}_{0}}{\sqrt{2}}\right)^{2}=\frac{1}{2} \varepsilon_{0} \mathrm{E}_{0}^{2}
$$
$$
=\varepsilon_{0} \mathrm{E}_{\mathrm{rm}}^{2}=\varepsilon_{0}\left(\frac{\mathrm{E}_{0}}{\sqrt{2}}\right)^{2}=\frac{1}{2} \varepsilon_{0} \mathrm{E}_{0}^{2}
$$
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