An electron, a neutron and an alpha particle have same kinetic energy and their de-Broglie wavelength are λ e , λ n and λ α respectively. Which statement is correct about their de-Broglie wavelengths?

Question

An electron, a neutron and an alpha particle have same kinetic energy and their de-Broglie wavelength are λ e , λ n and λ α respectively. Which statement is correct about their de-Broglie wavelengths?, λ e > λ n > λ α, λ e λ n > λ α, λ e λ n λ α, λ e > λ n λ α

MARKS App · Accepted Answer

According to de - Broglie theory, the wavelength λ = h p = h 2 m k λ ∝ 1 m (for same kinetic energy) The wavelength is inversely proportional to the root of mass of the particle. As m e m n m α So, λ e > λ n > λ α

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