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Question: Answered & Verified by Expert
An electron is accelerated under a potential difference of 64V, the de-Broglie wavelength associated with electron is [e=-1.6×1019 Cme=9.1×1031 kgh=6.623×1034 Js]
PhysicsDual Nature of MatterNEET
Options:
  • A 1.53  A o
  • B 2.53  A o
  • C 3.35  A o
  • D 4.54  A o
Solution:
1093 Upvotes Verified Answer
The correct answer is: 1.53  A o
Modified equation of de-Broglie wavelength λ= h2meV
λ= 12.27 A o V = 12.27 64 =1.534 A o

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