Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
An electron is constrained to move along the y-axis with a speed of 0.1 c (c is the speed of light) in the presence of electromagnetic wave, whose electric field is E=30j^sin1.5×107t-5×10-2x V m-1. where t in in seconds and x is im meters.The maximum magnetic force experienced by the electron will be: (given c=3×108 m s-1 and electron charge =1.6×10-19 Coloumbs
PhysicsMagnetic Effects of CurrentJEE MainJEE Main 2020 (05 Sep Shift 1)
Options:
  • A 3.2×10-18 N
  • B 2.4×10-18 N
  • C 4.8×10-19 N
  • D 1.6×10-19 N
Solution:
2189 Upvotes Verified Answer
The correct answer is: 4.8×10-19 N

In electromagnetic wave is E0B0=C
so maximum value of magnetic field is

B0=E0C

Fmax=qVBmax·sin90°

=qV0E0C N

1.6×10-19×0.1×3×108×303×108=4.8×10-19 N

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.