Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
An electron is moving in a circular path under the influence of a transverse magnetic field of 3.57×10-2 T. If, the value of em is 1.76×1011 C kg-1, the frequency of revolution of the electron is
PhysicsMagnetic Effects of CurrentNEETNEET 2016 (Phase 2)
Options:
  • A 1GHz
  • B 100MHz
  • C 62.8MHz
  • D 6.28MHz
Solution:
2957 Upvotes Verified Answer
The correct answer is: 1GHz

f=qB2πm=1.76×1011×3.57×10-22×3.14

=109 Hz=1 GHz.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.