An electron moving with velocity v along the axis approaches a circular current carrying loop as shown in the figure. The magnitude of magnetic force on electron at this instant is-

Question

An electron moving with velocity v along the axis approaches a circular current carrying loop as shown in the figure. The magnitude of magnetic force on electron at this instant is-, μ 0 4 e v i R 2 x ( x 2 ⁡ + R 2 ⁡ ) 3 / 2, μ 0 e v i R 2 x ( x 2 ⁡ + R 2 ⁡ ) 3 / 2, μ 0 4 π e v i R 2 x ( x 2 ⁡ + R 2 ⁡ ) 3 / 2, none of these

MARKS App · Accepted Answer

Direction of electron velocity is along magnetic field lines. Hence F = 0

Search any question & find its solution

Looking for more such questions to practice?