An electron of mass m e and a proton of mass m p = 1836 m e are moving with the same speed. The ratio of their de Broglie wavelength λ e l e c t r o n λ p r o t o n will be :

Question

An electron of mass m e and a proton of mass m p = 1836 m e are moving with the same speed. The ratio of their de Broglie wavelength λ e l e c t r o n λ p r o t o n will be :, 1836, 1 1836, 918, 1

MARKS App · Accepted Answer

Given mass of electron = m e Mass of proton = m p ∴ given m p = 1836 m e From de-Broglie wavelength λ = h p = h mv λ e λ p = m p m e = 1836 m e m e λ e λ p = 1836

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