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An electron of mass ' $m_e$ ' and a proton of mass ' $m_p$ ' are kept in a uniform electric field. The ratio of the acceleration of electron $\left(a_e\right)$ to the acceleration of proton $\left(a_p\right)$ is
PhysicsElectrostaticsMHT CETMHT CET 2022 (05 Aug Shift 2)
Options:
  • A $\frac{\mathrm{m}_{\mathrm{e}}}{\mathrm{m}_{\mathrm{p}}}$
  • B $\frac{\mathrm{m}_{\mathrm{p}}}{\mathrm{m}_{\mathrm{e}}}$
  • C one
  • D infinity
Solution:
2825 Upvotes Verified Answer
The correct answer is: $\frac{\mathrm{m}_{\mathrm{p}}}{\mathrm{m}_{\mathrm{e}}}$
Electrostatic force, $\mathrm{F}_{\mathrm{E}}=\mathrm{eE}$ (for both the particles)
The acceleration of electron, $a_e=\frac{F_E}{M_e}$ and
Acceleration of proton $a_p=\frac{F_E}{M_e}$
$\therefore \frac{\mathrm{a}_{\mathrm{e}}}{\mathrm{a}_{\mathrm{p}}}=\frac{\mathrm{M}_{\mathrm{p}}}{\mathrm{M}_{\mathrm{e}}}$

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