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Question: Answered & Verified by Expert
An electron revolves around the nucleus in a circular path with angular momentum $\overrightarrow{\mathrm{L}} . \mathrm{A}$ uniform magnetic field $\overrightarrow{\mathrm{B}}$ is applied perpendicular to the plane of its orbit. If the electron experiences a torque $\overrightarrow{\mathrm{T}}$, then
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Options:
  • A $\overrightarrow{\mathrm{T}} \| \overrightarrow{\mathrm{L}}$
  • B $\overrightarrow{\mathrm{T}}$ is anti-parallel to $\overrightarrow{\mathrm{L}}$
  • C $\overrightarrow{\mathrm{T}} \cdot \overrightarrow{\mathrm{L}}=0$
  • D Angle between $\vec{T}$ and $\vec{L}$ is $45^{\circ}$
Solution:
1410 Upvotes Verified Answer
The correct answer is: $\overrightarrow{\mathrm{T}} \cdot \overrightarrow{\mathrm{L}}=0$


$\vec{\tau}=0 \Rightarrow \vec{\tau} \cdot \vec{L}=0$

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