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An element crystallises in bcc type crystal structure with edge length of unit cell $300 \mathrm{pm} .$ Calculate radius of element?
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$1 \cdot 299 \times 10^{-8} \mathrm{~cm}$
$a=300 \mathrm{pm}=3 \times 10^{-8} \mathrm{~cm}$
For bcc unit cell, $r=\frac{\sqrt{3} a}{4}$
$\therefore r=\frac{1.732 \times 3 \times 10^{-8} \mathrm{~cm}}{4}=1.299 \times 10^{-8} \mathrm{~cm}$
For bcc unit cell, $r=\frac{\sqrt{3} a}{4}$
$\therefore r=\frac{1.732 \times 3 \times 10^{-8} \mathrm{~cm}}{4}=1.299 \times 10^{-8} \mathrm{~cm}$
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