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An element $E$ loses one $\alpha$ and two $\beta$ particle in three successive stages. The resultibg element will be
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Verified Answer
The correct answer is:
an isotope of $E$
Let $Z$ = atomic number
$M=$ atornic mass
Hence, ${ }_{Z} E^{M}$ and ${ }_{2} E^{M-4}$ has same atomic number with different atomic mass thus, they are isotopes.
$M=$ atornic mass
Hence, ${ }_{Z} E^{M}$ and ${ }_{2} E^{M-4}$ has same atomic number with different atomic mass thus, they are isotopes.
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