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Question: Answered & Verified by Expert
An element occuring in the bec structure has $12.08 \times 10^{23}$ unit cells. The total number of atoms of the element in these cells will be
ChemistrySolid StateVITEEEVITEEE 2018
Options:
  • A $24.16 \times 10^{23}$
  • B $36.18 \times 10^{23}$
  • C $6.04 \times 10^{23}$
  • D $12.08 \times 10^{23}$
Solution:
1061 Upvotes Verified Answer
The correct answer is: $24.16 \times 10^{23}$
There are two atoms in a $b c c$ unit cell. So, number of atoms in $12.08 \times 10^{23}$ unit cells $=2 \times 12.08 \times 10^{23}=24.16 \times 10^{23}$ atoms.

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