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An element occurring in the $b c c$ structure has $12.08 \times 10^{23}$ unit cells. The total number of atoms of the element in these cells will be
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The correct answer is:
$24.16 \times 10^{23}$
There are two atoms in a $b c c$ unit cell.
So, number of atoms in $12.08 \times 10^{23}$ unit cells $=2 \times 12.08 \times 10^{23}=24.16 \times 10^{23}$ atom .
So, number of atoms in $12.08 \times 10^{23}$ unit cells $=2 \times 12.08 \times 10^{23}=24.16 \times 10^{23}$ atom .
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