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An element with simple cubic close structure has edge length of unit cell $3.86 Å$. What is the radius of atom?
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Verified Answer
The correct answer is:
$1.93 \times 10^{-8} \mathrm{~cm}$
In simple cubic close structure
$$
\begin{aligned}
& \mathrm{a}=2 \mathrm{r} \\
& \mathrm{r}=\frac{\mathrm{a}}{2}=\frac{3.86}{2}=1.93 Å \\
& \mathrm{r}=1.93 \times 10^{-8} \mathrm{~cm} \\
& \left(1 \mathrm{~A}^{\circ}=10^{-10} \mathrm{~m}=10^{-8} \mathrm{~cm}\right)
\end{aligned}
$$
$$
\begin{aligned}
& \mathrm{a}=2 \mathrm{r} \\
& \mathrm{r}=\frac{\mathrm{a}}{2}=\frac{3.86}{2}=1.93 Å \\
& \mathrm{r}=1.93 \times 10^{-8} \mathrm{~cm} \\
& \left(1 \mathrm{~A}^{\circ}=10^{-10} \mathrm{~m}=10^{-8} \mathrm{~cm}\right)
\end{aligned}
$$
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