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An element \( X \) decays into element \( Z \) by two-step process.
\[
\begin{array}{l}
X \rightarrow Y+4 e \\
Y \rightarrow Z+2 e^{-} \text {then }:
\end{array}
\]
Options:
\[
\begin{array}{l}
X \rightarrow Y+4 e \\
Y \rightarrow Z+2 e^{-} \text {then }:
\end{array}
\]
Solution:
1258 Upvotes
Verified Answer
The correct answer is:
\( X \& Z \) are isotopes
The two processes are as follows:
\[
\mathrm{z}^{\mathrm{A}} X \rightarrow_{\mathrm{Z}-2}^{\mathrm{A}-{ }^{4} Y+{ }_{2}{ }^{4} \mathrm{He}}
\]
Since \( X \) and \( Z \) have same atomic number, that is, same number of protons but different atomic mass, that is, sum of
number of protons and neutrons.
We know isotopes are atoms with same number of protons but different number of neutrons. Therefore, \( X \) and \( Z \) are
isotopes.
\[
\mathrm{z}^{\mathrm{A}} X \rightarrow_{\mathrm{Z}-2}^{\mathrm{A}-{ }^{4} Y+{ }_{2}{ }^{4} \mathrm{He}}
\]
Since \( X \) and \( Z \) have same atomic number, that is, same number of protons but different atomic mass, that is, sum of
number of protons and neutrons.
We know isotopes are atoms with same number of protons but different number of neutrons. Therefore, \( X \) and \( Z \) are
isotopes.
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