An element, X has the following isotopic composition 200 X : 90% 199 X : 8.0 % 202 X : 2.0 % The weighted average atomic mass of the naturally occurring element X is closest to

Question

An element, X has the following isotopic composition 200 X : 90% 199 X : 8.0 % 202 X : 2.0 % The weighted average atomic mass of the naturally occurring element X is closest to, 204 amu, 198 amu, 197 amu, 200 amu

MARKS App · Accepted Answer

Average isotopic mass of X = 200 × 90 + 199 × 8 + 202 × 2 90 + 8 + 2 = 18000 + 1592 + 404 100 = 199.96 a m u ≈ 200 amu

Search any question & find its solution

Looking for more such questions to practice?